Your are given an array of positive integers nums
.
Count and print the number of (contiguous) subarrays where the product of all the elements in the subarray is less than k
.
Input: nums = [10, 5, 2, 6], k = 100 Output: 8 Explanation: The 8 subarrays that have product less than 100 are: [10], [5], [2], [6], [10, 5], [5, 2], [2, 6], [5, 2, 6]. Note that [10, 5, 2] is not included as the product of 100 is not strictly less than k.
0 < nums.length <= 50000
.0 < nums[i] < 1000
.0 <= k < 10^6
.
# @param {Integer[]} nums# @param {Integer} k# @return {Integer}defnum_subarray_product_less_than_k(nums,k)return0ifk < 2product=1i=0ret=0(0...nums.size).eachdo |j| product *= nums[j]whileproduct >= kproduct /= nums[i]i += 1endret += j - i + 1endretend
implSolution{pubfnnum_subarray_product_less_than_k(nums:Vec<i32>,k:i32) -> i32{if k < 2{return0;}letmut product = 1;letmut i = 0;letmut ret = 0;for j in0..nums.len(){ product *= nums[j];while product >= k { product /= nums[i]; i += 1;} ret += j - i + 1;} ret asi32}}